curl Authentication error on Images Only

I am trying to get information from a XML Rest API.

I can get everything but not the images.

I can display all info, but when it comes on images I get 401 error

Failed to load resource: the server responded with a status of 401 ().

Failed to load resource: the server responded with a status of 401 ()

My username and password are correct. The only way to get the images display is if I login to this API in a different window. Then all images are displayed.

Am I doing something wrong ? Here is my php code:

function CallAPI($url){
$curl = curl_init();
curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($curl, CURLOPT_USERPWD, "usr:psw");
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec($curl);
curl_close($curl);
return $result;
}

$a = "query SQL";
$asd = $database->query($a);
while($row = sqlsrv_fetch_array($asd)){
echo $url = $row['url']; // I can get this data display
$row['hotel_name'];
$a = CallAPI($url);
$axml = new SimpleXMLElement($a);
$img_link = $axml->item->images;
foreach ($img_link->image as $value) {
echo "<img src='".$value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink')."' class='img-responsive' />";
}


In the line $a = CallAPI($url); your backend server reads the data. But when it comes to images, you are only generating IMG tags. That means that the server is not fetching the images, but a webbrowser. And probably the browser does not have permissions to fetch those images.
– JustAC0der
Jun 21 at 11:03

$a = CallAPI($url);

@JustAC0der if I open a new window and login in that api I can display the images. But when send my user-pass through curl i can access everything in API except of images
– Maria
Jun 21 at 11:06

I am guessing, but it seems that you need two PHP scripts: one for fetching the main data (from $row['url']) and another one for fetching images (let's say we call it fetch_images.php). And you need to link from the first one to the second one, eg. '<img src="/fetch_images.php?url=' . urlencode($value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink')) . '">').
– JustAC0der
Jun 21 at 11:19

$row['url']

fetch_images.php

'<img src="/fetch_images.php?url=' . urlencode($value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink')) . '">'

1 Answer
1

So your problem must be that this link need authentication as well. So try make the call for $value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink') to pass user and pass.

$value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink')

So you code should look like this

while($row = sqlsrv_fetch_array($asd)){
$url = $row['url'];
$row['hotel_name']; // No use of this one, maybe you use it on your end
$a = CallAPI($url);
$axml = new SimpleXMLElement($a);
$img_link = $axml->item->images;
foreach ($img_link->image as $value) {
/*I am adding the link to a variable*/
$imgLinkFromValue = $value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink');
$img = CallAPI($imgLinkFromValue );
/* Now if you still get a link just pass the variable */
echo "<img src='$img->**link or href or anything you get**' class='img-responsive' />";
}


UPDATE

If you getting text or symbols maybe you have to use base64_encode().

base64_encode()

Try this :


$img = base64_encode(CallAPI($imgLinkFromValue ));
echo '<img src="data:image/jpeg;base64,' . $img . '" class="img-responsive" />'


$img = base64_encode(CallAPI($imgLinkFromValue ));
echo '<img src="data:image/jpeg;base64,' . $img . '" class="img-responsive" />'

You can always change the data inside src to png or gif, depends on what you need.

For more Info about base64_encode function you can use this link.
http://php.net/manual/en/function.base64-encode.php

Thanks for you answer but if I use CallAPI I cant get the image I get a wierd string and some symbols instead of the image
– Maria
Jun 29 at 11:00

@Maria I have updated my answer. Hope it helps :)
– DopeAt
Jun 29 at 11:06

Thank you so much it worked!!!!
– Maria
Jun 29 at 11:23

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