Convert XML to CSV not working


Convert XML to CSV not working



XML file Content:


<?xml version="1.0"?>
<servstate>
<title>2018-06-11 12:00:01</title>
<services>
<service>
<name>Oracle Weblogic AdminServer 1</name>
<state>RUNNING.</state>
</service>
<service>
<name>Oracle WebLogic NodeManager 1</name>
<state>RUNNING.</state>
</service>
<service>
<name>OracleProcessManager_1</name>
<state>RUNNING.</state>
</service>
<service>
<name>OracleProcessManager_2</name>
<state>RUNNING.</state>
</service>
<service>
<name>Oracle WebLogic NodeManager 2</name>
<state>RUNNING.</state>
</service>
<service>
<name>Oracle Weblogic AdminServer 2</name>
<state>RUNNING.</state>
</service>
</services>
</servstate>



I am new to PowerShell and written a script to parse the above XML as CSV file but I got the result as below.



Script:


$xml = [xml](Get-Content .monitoring_services.xml)
$xml.servstate.services.service |
Select-Object @(@{l="name";e={$_.name."#text"}}, @{l="state";e={$_.state."#text"}}) |
Export-Csv test.csv -NoTypeInformation



Result:



Expected result:



Could you help correct what went wrong the script?





@{l="name"... should be: @{n="name"...
– iRon
2 days ago


@{l="name"...


@{n="name"...





@iRon - Tried but same result ..
– Dheeban Chakkaravarthy
2 days ago





@iRon L for label or n for name are both valid. But that's not he point see RobinSidharth's answer.
– LotPings
2 days ago




2 Answers
2



Why don't you just use this?


$xml.servstate.services.service | Export-Csv test.csv -NoTypeInformation



Why are you complicating things? Why don't you just select the Name and the State and export it to CSV:


$xml.servstate.services.service | Select-Object Name, State | Export-Csv test.csv -NoTypeInformation



You don't need to create custom properties if you already have something that you need.





Since at that level there are only name and state the select isn't neccessary, and your answer differs in nothing from @RobinSidharth answer.
– LotPings
2 days ago






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