IndexOutOfRangeException on array [duplicate]

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int arr=new int[10]{1,21,32,43,54,65,76,87,98,10};

foreach(var i in arr)
{
Console.WriteLine("Elements [{0}]:{1}",arr[i],i);
}


I want the output like

element[0]: 1
element[1]: 21
...
element[9]: 10


by using foreach only, but I am getting this error:

foreach

Unhandled Exception: System.IndexOutOfRangeException: Index was
outside the bounds of the array. at Exercise1.Main () <0x41e47d70 +
0x0008c> in :0 [ERROR] FATAL UNHANDLED EXCEPTION:
System.IndexOutOfRangeException: Index was outside the bounds of the
array. at Exercise1.Main () <0x41e47d70 + 0x0008c> in :0

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3 Answers
3

i isn't the index, it's the element itselve. In the second iteration of your loop you try to access index 21 Console.WriteLine("Elements [{0}]:{1}",arr[21],21) which doesn't exist

i

Console.WriteLine("Elements [{0}]:{1}",arr[21],21)

change to for loop

for

int arr = new int[10] { 1, 21, 32, 43, 54, 65, 76, 87, 98, 10 };

for (int i =0;i< arr.Length;i++)
{
Console.WriteLine("Elements [{0}]:{1}",i ,arr[i]);
}


Try like this:

int j =0;
foreach(var i in arr)
{
Console.WriteLine("Elements [{0}]:{1}",j,i);
j++;
}


Thanks buddy, it helped me to learn.
– Aman Agrawal
2 days ago

The foreach keyword doesn't return the "index" of the elements. It returns the elements.

foreach

int arr = new int {1,21,32,43,54,65,76,87,98,10};

foreach (var el in arr)
{
Console.WriteLine("Element {0}", el);
}


In C# (unlike go) there is no direct construct that returns the i index plus the element arr[i]. You can have one (i using the for cycle and from there obtain arr[i]) or the other (using foreach)

i

arr[i]

i

for

arr[i]

foreach

Compare what you wrote with an array of strings to see its illogicity:

string

string arr = new string {"1","21","32","43","54","65","76","87","98","10"};

foreach (var el in arr)
{
Console.WriteLine("Element {0}", el);
}