2D array removes its elements after exiting the loop

Input is: hello world
The following program should record "hello" in words[0] and "world in words[1]

int rowIndex= 0;
char words [100][100];
for (int x = 0 ; x < input.length(); x++)
{
if (input[x]>='a'&&input[x]<='z' || input[x]>='A'&&input[x]<='Z')
// This condition is to avoid recording spaces in the array
{
words[rowIndex][x]= input[x];
cout << words[rowIndex][x]<<" ";
}
else {
rowIndex++;
// Once it finds a space, it records the following characters into the next index
cout << " Index: " << rowIndex <<endl;
}
}


output:
h e l l o
Index: 1
w o r l d

cout <<"Index 0: "<< words[0] <<endl;


Output: hello

cout <<"Index 1: "<< words[1] <<endl;


Output: " doesn't output anything" ( Why doesn't it output "world")

*****************************************************
Why doesn't the array hold the characters in words[1] and only holds the characters in words[0]
Note: I tried doing it with dynamic 2D array and same problem happened.

You don't reset x on a new word.
– Johnny Mopp
Jun 29 at 21:53

x

1 Answer
1

cout <<"Index 1: "<< words[1] exhibits undefined behavior, by way of accessing words[1][0] that was never initialized.

cout <<"Index 1: "<< words[1]

words[1][0]

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