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Exponent of a summation I am a very new python user. I am trying to calculate an exponent of a summation. The array has more parameters. import math a = [[1, 2, 3, 4], [5, 6, 7, 8]] def y(i): p = 2 total = 0 for j in range (4): total += math.exp(a[i][j] * (p**j)) return total Answer from this method: 7.89629603455e+13 7.89629603455e+13 The answer is way different than manual calculation below: y = math.exp(1*(2**0) + 2*(2**1) + 3*(2**2) + 4*(2**3)) Answer: 1.9073465725e+21 1.9073465725e+21 Can you post expected answer for this – Venkata Gogu Jun 29 at 17:47 The expected output has the sum inside the exponential, while in the loop you take the exponential first and then sum. These aren't the same. – Jay Calamari Jun 29 at 17:50 ...

Interfacing octave with C# I have developed a program in Octave to which I would like to add a GUI layer. I want to create an executable program in C# that I can distribute but want to stick with the linear algebra constructs of Octave without having to implement them on my own. Particularly, I want basic matrix, vector operations and optimization functions (like fminunc and fmincg ). fminunc fmincg What is the best way to achieve this? Appropriate C# linear algebra library, perhaps? You should edit your title to match your question, you might get more people interested. – jv42 Nov 6 '11 at 12:32 5 Answers 5 There are lots of math libraries for c#. Math.NET Numerics seems to be a good free alternative. There are also commercial implementations. Anot...

Maximal unique continuous subsequence Given a sequence of integer numbers: a[0], a[1], a[2], ..., a[n] Subsequence a[i]...a[j] is unique if the following is true: a[i]...a[j] for each x, y between i and j and x != y: a[x] != a[y] I need to find length of maximal unique , continuous subsequence My approaches: I tried many heuristic approaches, but they didn't work. Then I wrote bruteforce, it gave O(n^3) complexity, which is impossible to calc if n = 10^6 O(n^3) n = 10^6 ans = 1 for i in [0, n] for j in [i, n] if unique a[i]...a[j] ans = max(ans, j-i+1) I think it is typical dp problem, but don't know how to proceed dp 4 Answers 4 Create hashmap (or use boolean array if range of values is rather short). Make two indexes - left and right , set them in the beginning. left right Move right index. At every step check if t = A[right] already is in map. Stop when ...

What function(s) determine the max or min of two integers? Which _STD function(s) return the max, or min of 2 integers, signed or unsigned? Is it the max, min in the math.h header library or what could they be? Possible duplicate of Use of min and max functions in C++ – Radiodef 2 days ago 3 Answers 3 std::min and std::max in the <algorithm> library. As they're templates they return the min and max for every type that implements the < operator (or you can supply a functor for your custom comparison). std::min std::max <algorithm> < See Algorithms library (link to cppreference.com). You can use the new algorithm introduced in C++11( template<class T> pair<const T&, const T&> minmax(const T& a, const T...