Finding different type of single quotes in javascript

My requirement: There are three strings with single quotes of different types(like -> '‘’) and when I search with a single quote(i.e -> ') I should get the index of the single quote in all the cases.

e.g:

var str1 = "this is someone's question"
var str2 = "this is someone‘s question"
var str3 = "this is someone’s question"


str.indexOf("'"); -> This statement should find single quotes (', ‘ and ’) in all the three variables. Just like the google chrome find works in web page search.
Thanks in advance

str.indexOf("'");

they're different characters. you will need 3 statements or regex
– Philipp Sander
Jun 29 at 11:03

Google likely either normalizes this, or just searches for the different quotes.
– Dave Newton
Jun 29 at 11:03

.search(/[‘'’]/)
– Keith
Jun 29 at 11:07

.search(/[‘'’]/)

2 Answers
2

var index = /['‘’]/.exec(str3).index

var index = /['‘’]/.exec(str3).index

Using regex & .search() you can detect the single-quotes:

.search()

const regex = /('|‘|’)/gm;
var str1 = "this is someone's question"
var str2 = "this is someone‘s question"
var str3 = "this is someone’s question"

console.log("Found single-quote @ index: " + str1.search(regex));
console.log("Found single-quote @ index: " + str2.search(regex));
console.log("Found single-quote @ index: " + str3.search(regex));

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