Load entire dict into a particular dataframe cell


Load entire dict into a particular dataframe cell


df =
columnA columnAB
row1 xxx
row2 yyy
row3 zzz
row4 xyx

expected df =
columnA columnAB columnB
row1 xxx [('A1(80)', ['BB11', 'A11', 'A21']), ('B1(70)', ['CC55', 'HH21']), ('C1(60)', ['KK88'])]
row2 yyy
row3 zzz
row4 xyx

from collections import defaultdict

d1, d2 = defaultdict(int), defaultdict(list)

d = {'A1BB11': 10,
'B1CC55': 20,
'A1A11': 30,
'A1A21': 40,
'B1HH21': 50,
'C1KK88': 60
}

for k, v in d.items():
prefix = k[:2]
d1[prefix] += v
d2[prefix].append(k[2:])

final = {'{}({})'.format(k, d1[k]): v for k, v in d2.items()}

print(final)
# {'A1(80)': ['BB11', 'A11', 'A21'],
# 'B1(70)': ['CC55', 'HH21'],
# 'C1(60)': ['KK88']}



Now I need to load this data in a dataframe cell, I tried converting this into list and load


final = sorted(final.items())
# type(final) = <class 'list'>

df.loc[df['columnA'].str.contains('row1', na=False), 'columnB'] = final



But I run into error
ValueError: setting an array element with a sequence



could you suggest a way to handle this





what's your df structure? Also, post the final expected result
– RomanPerekhrest
Jun 29 at 18:42



df





updated the problem statement with df and expected df
– Rahul
Jun 29 at 19:14




1 Answer
1



Assuming columnB is already an exiting column of the dataframe, try this:


columnB


df.loc[df['columnA'].str.contains('row1', na=False), ['columnB']] =
df.loc[df['columnA'].str.contains('row1', na=False), ['columnB']].applymap(lambda x: final)



if columnB doesn't exit, reindex the dataframe before applymap as:


columnB


applymap


df = df.reindex(columns=['columnA', 'columnAB', 'columnB'], fill_value='')



or insert it with empty value


df['columnB'] = ''





Just reindex the dataframe before applymap, I updated the answer
– xhamr
Jun 29 at 20:41


applymap





It says series object has no Attribute applymap
– Rahul
Jun 29 at 20:59





It throws following error, AttributeError: 'Series' object has no attribute 'applymap'
– Rahul
Jun 29 at 21:10






Sorry, i forgot the brackets around 'columnB', check the updated answer
– xhamr
Jun 29 at 22:12






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