Regex ignore multiple wrong placed quotes


Regex ignore multiple wrong placed quotes



From this input:


""" "01-01-2000""" " ",""" "Bank123""" "", "" ""Example text" " "",



I want to extract:


01-01-2000
Bank123
Example text



I managed this:


(["'])(?:(?=(?))2.)*?1



But if fails if it comes to deal with many wrong placed quotes. Any ideas?





Try "b(.*?)b"
– Wiktor Stribiżew
Jun 29 at 8:41


"b(.*?)b"





Or, B"b(.*?)b"B. Can the values you want to extract contain "? Why did you use a regex that matches escaped "?
– Wiktor Stribiżew
Jun 29 at 8:48



B"b(.*?)b"B


"


"





Could you please clarify?
– Wiktor Stribiżew
Jun 29 at 9:57




3 Answers
3



As I see, you are interested in strings which:


"



So the intuitive solution is [a-zd][^"]* with gi options
(global, case insensitive).


[a-zd][^"]*


gi



For your given example, perhaps it could be an option to match a whitespace or a double quote zero or more times [ "]* to match what comes before the value between the inner double quotes.


[ "]*



Then match that double quote and capture in a group not a double quote or a newline ([^"rn]+) using a negated character class.


([^"rn]+)



At the end match the closing double quote followed by zero or more times a whitespace or a double quote which will match what comes after so the group does not match a whitespace between double quotes.



[ "]*"([^"rn]+)"[ "]*


[ "]*"([^"rn]+)"[ "]*



There are various options to do so:


1) ([d-ws][d-ws]+)
2) ([d-ws]{2,})
3) "b(.+?)b"
4) b([^"]{2,})b



Demo : https://regex101.com/r/jPXqKv/1



Test:


""" "01-01-2000""" " ",""" "Bank123""" "", "" ""Example text" " ""



Match:


Match 1
Full match 5-15 `01-01-2000`
Group 1. 5-15 `01-01-2000`
Match 2
Full match 28-35 `Bank123`
Group 1. 28-35 `Bank123`
Match 3
Full match 48-60 `Example text`
Group 1. 48-60 `Example text`






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