Splitting strings with Javascript without using for loop


Splitting strings with Javascript without using for loop



I have following string:


var myString = " https://image.ibb.co/fShWGd/samhily.jpg
https://image.ibb.co/iDbDUy/ramhily.jpg
https://image.ibb.co/cvbf9y/devoly.jpg "



ANd I would like to get the following array:


var myArray = ["https://image.ibb.co/fShWGd/samhily.jpg","https://image.ibb.co/iDbDUy/ramhily.jpg", "https://image.ibb.co/cvbf9y/devoly.jpg".



Any ideas on how I would do that?



Tried this:


myArray.split(/(s+)/).filter( function(e) { return e.trim().length > 0; } );



But I get t when I do console.log(myArray[1])


t


console.log(myArray[1])





Tried anything ?
– j08691
Jun 29 at 17:32





"I have following string". No you don't. You can't have that code in any javascript anywhere without getting a syntax error.
– gforce301
Jun 29 at 17:34





Does your string really have all that whitespace?
– Mark_M
Jun 29 at 17:35





is your string correct? having space between 2 urls?
– NullPointer
Jun 29 at 17:36






for what you tried, don't you mean to start that line with myString?
– Garrett Motzner
Jun 29 at 17:48


myString




7 Answers
7



You can trim() the string first, then split on whitespace. This saves you from having to loop over the results again map():


trim()


map()




var myString = ` https://image.ibb.co/fShWGd/samhily.jpg
https://image.ibb.co/iDbDUy/ramhily.jpg
https://image.ibb.co/cvbf9y/devoly.jpg `

console.log(myString.trim().split(/s+/))



You want to use split to split on the new lines:




var myString = ` https://image.ibb.co/fShWGd/samhily.jpg
https://image.ibb.co/iDbDUy/ramhily.jpg
https://image.ibb.co/cvbf9y/devoly.jpg `

var result = myString.split(/rn|n/).map(i => i.trim())

// Result of all items
console.log(result)

// Result of first item in the array
console.log(result[1])



you can use .match with a Regex to match the substrings starting with https and ending with jpg , this will match them even if they are in a single line :


https


jpg




var myString = `https://image.ibb.co/fShWGd/samhily.jpg
https://image.ibb.co/iDbDUy/ramhily.jpg
https://image.ibb.co/cvbf9y/devoly.jpg`

var result = myString.match(/https(.*)jpg/g)

console.log(result)



if your string having space in between urls then you can do like below:




var myString = " https://image.ibb.co/fShWGd/samhily.jpg https://image.ibb.co/iDbDUy/ramhily.jpg https://image.ibb.co/cvbf9y/devoly.jpg "

console.log(myString.trim().split(" ").map(i => i))



for case of whitespace try this:




var myString = ` https://image.ibb.co/fShWGd/samhily.jpg
https://image.ibb.co/iDbDUy/ramhily.jpg
https://image.ibb.co/cvbf9y/devoly.jpg `

console.log(myString.trim().split(/rn|n/).map(value => value))



You can use trim split filter and map to achive it.


var myString = ` https://image.ibb.co/fShWGd/samhily.jpg
https://image.ibb.co/iDbDUy/ramhily.jpg
https://image.ibb.co/cvbf9y/devoly.jpg `

myString.trim().split(/rn|n/).filter(Boolean);





That's not what the OP's input string looks like and this won't work not the OP's string.
– Mark_M
Jun 29 at 17:49






@Mark_M update my solution.
– anshu purohit
Jun 29 at 17:54



A simple reg exp to match anything by spaces would get what you want.




var myString = ` https://image.ibb.co/fShWGd/samhily.jpg
https://image.ibb.co/iDbDUy/ramhily.jpg
https://image.ibb.co/cvbf9y/devoly.jpg `

console.log(myString.match(/[^s]+/g))



Assuming your string has all that whitespace (and therefore would need to be quoted with back-ticks (`)):


`


var myString = ` https://image.ibb.co/fShWGd/samhily.jpg
https://image.ibb.co/iDbDUy/ramhily.jpg
https://image.ibb.co/cvbf9y/devoly.jpg `

myString.trim().split(/s+/)



First, this gets rid or whitespace on the ends of myString, then it splits on any group of whitespace (s) characters.


myString


s






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