TypeError in python which says that dict object is not callable

I'm new to Python. I am getting the error TypeError:dict object is not callable. I haven't used dictionary anywhere in my code.

TypeError:dict object is not callable

def new_map(*arg1, **func):
result =
for x in arg1:
result.append(func(x))
return result


I tried calling this function as follows:

new_map([-10], func=abs)

new_map([-10], func=abs)

But when I run it, I am getting the above error.

5 Answers
5

Seems like you are using arbitrary arguments when they are not required. You can simply define your function with arguments arg1 and func:

arg1

func

def new_map(arg1, func):
result =
for x in arg1:
result.append(func(x))
return result

res = new_map([-10], abs)

print(res)

[10]


For detailed guidance on how to use * or ** operators with function arguments see the following posts:

*

**

Thanks for you help but arg1 is iterable here. So I had put *arg1. How to differentiate key word argument from positional argument if I don't put a * before func?
– Shreesakhi
Jun 29 at 11:48

Try it, test it, you don't need *! You have 2 arguments, one of them is an iterable, the other is a function. Your function doesn't need to unpack arbitrary arguments, because they are well defined.
– jpp
Jun 29 at 11:53

*

when tried to test your code with the following test case: new_map(-10, -20, -30, func=abs). It shows the following error: new_map() takes 1 positional argument but 3 positional arguments (and 1 keyword-only argument) were given
– Shreesakhi
Jun 29 at 11:58

Use input [-10, -20, -30] instead, i.e. new_map([-10, -20, -30], abs). Don't choose lists or unpacked elements arbitrarily, stick with one or the other.
– jpp
Jun 29 at 11:58

[-10, -20, -30]

new_map([-10, -20, -30], abs)

Since the arbitrary argument may vary for each test case, I have used it that way
– Shreesakhi
Jun 29 at 12:01

The ** prefix says that all of the keyword arguments to your function should be grouped into a dict called func. So func is a dict and func(x) is an attempt to call the dict and fails with the error given.

**

dict

func

func

dict

func(x)

dict

You have used a dictionary by mistake. When you defined new_map(*arg1, **func), the func variable gathers the named parameter given during the function call. If func is supposed to be a function, put it as first argument, without * or **

new_map(*arg1, **func)

func

func

*

**

func is a dictionary in your program. If you want to access value of it then you should use not (). Like:

func

dictionary

()

def new_map(*arg1, **func):
result =
for x in arg1:
result.append(func[x]) #use , not ()
return result


If func is a function to your program then you should write:

func

function

def new_map(*arg1, func):
result =
for x in arg1:
result.append(func(x)) #use , not ()
return result


Or a simple list comprehension:

def new_map(arg1, func):
return [func(i) for i in arg1]

out = new_map([-10], func=abs)
print(out)


Output:

[10]


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