How can I check that function really get a variable that defined as const?

Given the following code:

template <class Func>
void f(Func func , int* param){
func(/* how can I send "param" as const "int*" */);
}


How can I do it so that if f don't get the variable as const - so we will get error ?

f

Some minimal code would be handy for an answer to fill in the blank.
– chris
Jun 29 at 9:10

@chris I edited my question (and I added example in order to clarify my question).
– Software_t
Jun 29 at 9:17

Which one do you want? "Const pointer" or "pointer to const"?
– Nicky C
Jun 29 at 9:19

1 Answer
1

If you want to make sure that f accepts a pointer to const-qualified int you can cast function argument appropriately:

f

f(static_cast<int const *>(param));


Alternatively, if you want to make sure that f accepts a reference to const-qualified pointer you can add const qualifier to function argument:

f

void f(Func f , int * const param)


I thought about it too, but it's not doing the opposite thing? Namely, static_cast don't remove the "const" from param?
– Software_t
Jun 29 at 9:19

static_cast

@Software_t It is const_cast that removes const
– VTT
Jun 29 at 9:20

const_cast

const

I am sorry, you right. Can you explain if I can do it with dynamic_cast in this case or not (and why) ?
– Software_t
Jun 29 at 9:27

dynamic_cast

@Software_t: Sure, that would degenerate to a static_cast there. Imho, they should have added no_cast when they added all the explicit casts, which is enough here.
– Deduplicator
Jun 29 at 9:30

static_cast

no_cast

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